Originally Posted By: Finz
Originally Posted By: Shannow
Count on those two answers being wrong...
If ethanol had zero calorific value, E10 should lose 10% of it's miles per pound.
But it doesn't...it's got 61% of the energy per pound, so E10 in theory will drop about 4% mileage per pound of fuel...
Take half the ethanol content as a probable mileage loss, unless you are playing high ethanol contents with engines that are optimised to use it
Shannow... would you run this by my again please? I don't follow - are you saying:
E10 addition to fuel sacrifices 4% per pound? So a 30 mpg car would lose 24% mpg based on a 6 pound gallon of E10 fuel and run at 23 mpg?
Sorry, I switched to energy content per Kilogramme, which is my native tongue, changed it to a percentage, then used it per pound of "ingredient" in the fuel brew.
e.g.
Petrol has 44MJ/Kg (think BTU per pound), Ethanol has 26.9 MJ/Kg...therefore a KG of ethanol has 61% of the energy of a KG of petrol, and same pound for pound.
So E10 has "90" (for the 90% petrol) plus "6.1" for the 10%x61% for the ethanol, and loses the about 4% number.
to turn it into volume, you need another conversion. Ethanol is pretty specific at an S.G. of 0.785 (grammes per CC, water SG = 1), while petrol has a range, 0.72 to 0.79 (or low 80s for some Oz stuff that offers "high mileage at high cost"), making it more complicated to do volumes.