I don't think you can convert count to percent. For instance, if you had 1 ml of oil with a .25 ml particle, you'd have 1/ml but it would represent 25% of the volume.
OTOH, if you had 1 ml of oil with a thousand 5 micron particles you would have an aggregate particle volume of 64450 cubic microns. This is based on a presumption of uniform 5 micron spheres with a volume of 64.45 cubic micron per sphere (V = 4*3.1416*2.5*2.5*2.5/3). 1 ml contains 10^9 cubic microns (1000*1000*1000). So, 1 ml with a thousand 5 micron particles would contain 64450/10^9 = 0.0000064450 percent.
If the particles were 100 microns, the aggregate particle volume would be 5.24x10^8 and the percentage would be 52.4 percent.
So, without knowing the average size of the particles, there is no way of converting count/ml to a percentage.