What do I set my torque wrench to in this example?

Status
Not open for further replies.
Joined
Apr 27, 2010
Messages
18,202
Location
Suburban Washington DC
Tightening a camshaft sprocket bolt and no room to get the torque wrench on it directly. It calls for 66 lb. ft. The distance from the center of the box end wrench to the square drive of the cheater bar is 18 inches. What do I set the torque wrench to?

[Linked Image]
 
Make sure the bolt isn't a torque to yield bolt if your reusing it. If the vehicle is European, there's a good chance it is.
 
Total Wild Guess. 44 should be plenty 18 is 3/2 of 12 and 44 is 2/3 of 66. Never used a torque spec when tightening a sprocket bolt .
27.gif
 
Originally Posted by Cdn17Sport6MT
When at 90 degrees, there is no modification. When "A" is negative... you have to have a higher indicated torque on the wrench.


Yeah this. You can get a little ratchet with 3/8" or 1/2" drive in-and-out if the setup you have won't give you 90.

32.gif
That cheater bar looks neet.
 
so you would take the org length of the torque wrench (L)

find the total length the wrench and cheater bar (A)

and then divide [L /(L+A)] x required torque(66)
Which in this case I think you would end up at about half or 33lb-ft


example numbers if the torque wrench is 16" and the cheater/wrench combo is 18"

you would take 16/(16+18) or .47 x 66 =31
 
Originally Posted by SLO_Town
Originally Posted by eljefino
32.gif
That cheater bar looks neet.


It does! I just ordered one from Bezos.

Scott


Me too!

Far more elegant (and likely to fit) than my current cheater pipe (an old jack handle).
 
Originally Posted by Astro14
Originally Posted by SLO_Town
Originally Posted by eljefino
32.gif
That cheater bar looks neet.


It does! I just ordered one from Bezos.

Scott


Me too!

Far more elegant (and likely to fit) than my current cheater pipe (an old jack handle).

See, aitkovi, you're good for something! :)

Scott
 
Originally Posted by Rand
so you would take the org length of the torque wrench (L)

find the total length the wrench and cheater bar (A)

and then divide [L /(L+A)] x required torque(66)
Which in this case I think you would end up at about half or 33lb-ft


example numbers if the torque wrench is 16" and the cheater/wrench combo is 18"

you would take 16/(16+18) or .47 x 66 =31



That looks right to me..
 
It's called a wrench extender. Great for getting more leverage on a wrench when a pipe wouldn't fit over the end of it. Much safer than latching two wrenches together.
 
Status
Not open for further replies.
Back
Top