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#4707793 - 03/26/18 07:16 PM Chainsaw Tooth Velocity
MolaKule Offline


Registered: 06/05/02
Posts: 19138
Loc: Iowegia - USA
If a chainsaw sprocket of 1.5" Radius is rotating at 4300 rpm, how many feet will any one chain tooth travel in 1 second?

Recall that Tangential velocity Vt = w*R, where omega w is the velocity of the sprocket in radians per second and R is radius of the sprocket.

Of course, we're going to lube the chain with a tacky 30 grade oil called, "Bar and Chain oil." smile









Edited by MolaKule (03/26/18 07:22 PM)

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#4707803 - 03/26/18 07:23 PM Re: Chainsaw Tooth Velocity [Re: MolaKule]
jhellwig Offline


Registered: 07/01/13
Posts: 1570
Loc: Ottumwa, Iowa
35.83repeating?(I forgot the repeating symbol and an to lazy to look it up.)

Edit that would be the linear speed though not the tip speed around the sprocket.

Edit 2 I did it the dumb way not the formula way.

Edit 3 I didn't do it right at all. 3377 ft per second.


Edited by jhellwig (03/26/18 07:40 PM)
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#4707811 - 03/26/18 07:28 PM Re: Chainsaw Tooth Velocity [Re: MolaKule]
Rand Online   content


Registered: 08/20/03
Posts: 12740
Loc: NE,Ohio

so 3" is the diameter *pi *4300(rpm) / 12 (inches in feet)

seems way off but 3377ft?
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#4707826 - 03/26/18 07:44 PM Re: Chainsaw Tooth Velocity [Re: MolaKule]
IndyIan Offline


Registered: 09/23/08
Posts: 9117
Loc: Ontario, Canada
To lazy for math, but whatever 50-60mph is in feet per second. Makes you think saw pants are a good idea!
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#4707830 - 03/26/18 07:49 PM Re: Chainsaw Tooth Velocity [Re: MolaKule]
cpayne5 Offline


Registered: 12/28/05
Posts: 619
Loc: Virginia
~56.3'?

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#4707831 - 03/26/18 07:49 PM Re: Chainsaw Tooth Velocity [Re: MolaKule]
MolaKule Offline


Registered: 06/05/02
Posts: 19138
Loc: Iowegia - USA
The velocity of the chain is approximately equal to the tangential velocity of the sprocket.

Hint: First convert RPM to radians/s.

So in one second the tooth will have traveled X feet????

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#4707834 - 03/26/18 07:51 PM Re: Chainsaw Tooth Velocity [Re: MolaKule]
A_Harman Offline


Registered: 10/01/10
Posts: 6950
Loc: Michigan
4300 rev/min x 2*pi radians/rev x 1 min/60 sec x 1.5 in x 1 ft/12 in = 56.28 ft/sec, or about 38 mph.
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#4707836 - 03/26/18 07:53 PM Re: Chainsaw Tooth Velocity [Re: IndyIan]
MolaKule Offline


Registered: 06/05/02
Posts: 19138
Loc: Iowegia - USA
Originally Posted By: IndyIan
Makes you think saw pants are a good idea!


Ha ha, for sure. LOL

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#4707839 - 03/26/18 07:56 PM Re: Chainsaw Tooth Velocity [Re: MolaKule]
JimPghPA Offline


Registered: 08/22/09
Posts: 3859
Loc: Pittsburgh,PA U.S.A.
4300 RPM/60 seconds per minute = 71.66 revolutions per second.

The circumference of a circle = pi X Diameter or pi X 2 X Radius

Circumference of a 3 inch diameter circle is 3 X 3.14 = 9.42 inches

71.66 revolutions X 9.42 inches circumference = 675.0372 inches per second.

Divide by 12 to get feet per second.

675.0372/12 = 56.2531 feet per second
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#4707842 - 03/26/18 07:57 PM Re: Chainsaw Tooth Velocity [Re: cpayne5]
MolaKule Offline


Registered: 06/05/02
Posts: 19138
Loc: Iowegia - USA
Originally Posted By: cpayne5
~56.3'?


In what units?

Originally Posted By: A_Harmon
4300 rev/min x 2*pi radians/rev x 1 min/60 sec x 1.5 in x 1 ft/12 in = 56.28 ft/sec, or about 38 mph.


So any one tooth will travel how many feet in one second?


Originally Posted By: JiminPA
675.0372/12 = 56.2531 feet per second


So any one tooth will travel how many feet in one second?


Edited by MolaKule (03/26/18 07:59 PM)

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#4707848 - 03/26/18 08:03 PM Re: Chainsaw Tooth Velocity [Re: MolaKule]
JimPghPA Offline


Registered: 08/22/09
Posts: 3859
Loc: Pittsburgh,PA U.S.A.
88 feet per second = 60 MPH


(56.2531 / 88) X 60 = 38.35 MPH
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Boy will I be happy when ALL vehicles on public roads are autonomous.


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#4707849 - 03/26/18 08:03 PM Re: Chainsaw Tooth Velocity [Re: MolaKule]
cpayne5 Offline


Registered: 12/28/05
Posts: 619
Loc: Virginia
Originally Posted By: MolaKule
Originally Posted By: cpayne5
~56.3'?


In what units?


Feet, as indicated by the apostrophe (lazy man's prime). smile

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#4707851 - 03/26/18 08:05 PM Re: Chainsaw Tooth Velocity [Re: MolaKule]
JimPghPA Offline


Registered: 08/22/09
Posts: 3859
Loc: Pittsburgh,PA U.S.A.
Originally Posted By: MolaKule
Originally Posted By: cpayne5
~56.3'?


In what units?

Originally Posted By: A_Harmon
4300 rev/min x 2*pi radians/rev x 1 min/60 sec x 1.5 in x 1 ft/12 in = 56.28 ft/sec, or about 38 mph.


So any one tooth will travel how many feet in one second?


Originally Posted By: JiminPA
675.0372/12 = 56.2531 feet per second


So any one tooth will travel how many feet in one second?


Answer 56.28 Feet per second
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Boy will I be happy when ALL vehicles on public roads are autonomous.


JimPghPa


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#4707855 - 03/26/18 08:08 PM Re: Chainsaw Tooth Velocity [Re: cpayne5]
MolaKule Offline


Registered: 06/05/02
Posts: 19138
Loc: Iowegia - USA
Originally Posted By: cpayne5
Originally Posted By: MolaKule
Originally Posted By: cpayne5
~56.3'?


In what units?


Feet, as indicated by the apostrophe (lazy man's prime). smile


Sorry, didn't see the apostrophe, but yes you and Mr. Harmon and Jim were all correct, just trying to get everyone to answer the question of "how many feet of travel in 1 second?"

Any one tooth or chain link will travel 56.25 feet in any 1 second if the chain's linear velocity is 56.25 ft./sec. thumbsup


Edited by MolaKule (03/26/18 08:20 PM)

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#4707860 - 03/26/18 08:11 PM Re: Chainsaw Tooth Velocity [Re: MolaKule]
A_Harman Offline


Registered: 10/01/10
Posts: 6950
Loc: Michigan
What's the trick here? Are you going to nitpick about how tall the teeth are, which would change the tangential velocity.
How long is the bar? What is the radius of the drive sprocket?

Am I biting on your hook?
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1985 Z51 Corvette track car
2002 Camaro Z28 LS1/6-speed
2001 Dodge Ram 2500 diesel
1972 GMC 1500 shortbed project truck

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