Originally Posted By: Jetronic
Originally Posted By: Cardenio327
If the battery has a shorted cell, yes, very hard on the alternator.
If the battery is just weak, no, it is much easier to charge than a strong battery.
A weak battery, however, is harder on the electrical system in general, especially the starter, as the lower the voltage drops while cranking, the higher the current flow and more heat is produced.
erhm, the lower the voltage, the lower the current aswell... P=U².R. If the voltage drops, power drops dramatically...
I couldn't find your formula with Google, who knows what it's supposed to be. I did find this:
Originally Posted By: Random Internet Search
With regard to a DC motor, the voltage across the motor, minus IR losses, is proportional to the speed or RPMs of the motor. The current through the motor is proportional to the torque produced by the motor. Normally the back EMF created by the speed of the motor opposes the voltage being applied and limits the amount of current the motor draws and thus it's torque. As more and more load is applied to the motor, the motor slows reducing its back EMF allowing more current to flow, producing more torque.
With a lower applied voltage to the motor not only will the motor be turning slower, which reduces the back EMF and allows more current to flow, the losses such as the internal battery resistance, the cable loss and the IR drop in the motor become more important. This may mean that the motor may not have the speed or torque to turn over the engine and stall. When the motor stalls there is no longer any back EMF and all the current goes towards heating up the motor windings and that can damage the motor.
From what I've observed in real life, the lower the battery voltage swings during cranking, the more current is drawn, and more heat is produced by the starter, cables, and terminals. This would be caused by the resistance in the circuit and the increased current demands of the DC starter motor.